计算某月某日为一年中第几天

编写函数dayOfYear(year, mouth,day),使得函数返回由这三个参数确定的那一天是一年中的第⼏天.

int dayOfYear(int year, int mouth, int day);  //函数声明

int main {

//定义年月日并且输入后保存到三个变量中

    int year = 0;
    int mouth =0;
    int day = 0;
    printf("请输入年月日(xxxx.xx.xx):");
    scanf("%d.%d.%d", &year, &mouth, &day);
    int num = dayOfYear(year, mouth, day);//调用函数
    printf("今天是这一年的第%d天", num);

return 0;
    }

int dayOfYear(year, mouth, day){
    int value = 0;//用来存储某天为那年的第几天
    int temp = 0;//定义一个变量存储每个月的天数

    //从第一个月开始循环天数,累计每个月天数和
    for (int i =1; i < mouth; i++) {

        //判断是否为闰年, 2月天数特殊
        if (year % 4 ==0) {
            if (i == 2) {
                temp =29;
            }
        continue;
        }
        //判断当月天数
        switch (i) {
            case 1:
            case 3:
            case 5:
            case 7:
            case 8:
            case 10:
            case 12:
                temp =31;
                break;
            case 4:
            case 6:
            case 9:
            case 11:
                temp = 30;
                break;
            case 2:
                temp = 28;
                break;
            default:
                break;
        }

        //累计当月之前的天数
        value += temp;
        }

    //总天数
    value = value + day;

return value;

}