HDU1002

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output
For each test case, you should output two lines. The first line is “Case #:”, # means the number of the test case. The second line is the an equation “A + B = Sum”, Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input
2
1 2
112233445566778899 998877665544332211

Sample Output
Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

package com.hdu;

import java.math.BigInteger;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

//A + B Problem II 1002
public class BigIntegerAB {
    public static void main(String [] args){
        Scanner input = new Scanner(System.in);
        List list = new ArrayList();
        int num = input.nextInt();
        input.nextLine();
        while(num > 0){
            BigInteger bigA = new BigInteger(input.next());
            BigInteger bigB = new BigInteger(input.next());
            BigInteger sum = bigA.add(bigB);
            list.add(bigA+" + "+bigB+" = "+sum);
            num -- ;
        }
        for (int i = 0; i <list.size(); i++){
            if(i == list.size()-1){
                System.out.println("Case "+(i+1)+":");
                System.out.println(list.get(i));
            }else{
                System.out.println("Case "+(i+1)+":");
                System.out.println(list.get(i));
                System.out.println();
            }
        }
    }
}

这个题目就是大数，没有逻辑。就是输出格式很恶心：
1.注意case的c是大写。
2.case后面有一个冒号。
3.两个case之间要空行，最后一个case不要留空行。