如果是简单或者标准格式的xml,可以使用xstream,之前映射成一个对象然后去修改操作,很简单。
但是如果是负杂的,而且有可能xml的节点内容不一样,该怎么做呢?
一下是我的一种解决方法,当然可以利用其他的jar包如dom4j等,应该更简单一些
StringReader sr = new StringReader(strXml);
InputSource is = new InputSource(sr);
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder=factory.newDocumentBuilder();
Document doc = builder.parse(is);
NodeList list = doc.getElementsByTagName("extract4DB");
for (int i = 0; i < list.getLength(); i++) {
Element ele = (Element) list.item(i);
String brandName = ele.getAttribute("name");
if(brandName.equals("ts1")){
NodeList list1 = ele.getElementsByTagName("datasourceNames");
Element ele1 = (Element) list1.item(0);
String[] s = ele1.getTextContent().split(";");
ele1.setTextContent(s[0]+"_standby;");
System.out.println(ele1.getTextContent());
}
}
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
t.setOutputProperty("encoding","utf-8");
ByteArrayOutputStream bos = new ByteArrayOutputStream();
t.transform(new DOMSource(doc), new StreamResult(bos));
String xmlchange = bos.toString();
System.out.println(xmlchange);
strXml:是附件中的字符串