import pandas as pd
train = pd.read_csv('data/train.csv')
testA = pd.read_csv('data/testA.csv')
print('Train data shape:',train.shape)
print('TestA data shape:',testA.shape)
Train data shape: (800000, 47)
TestA data shape: (200000, 48)
train.head()
id | loanAmnt | term | interestRate | installment | grade | subGrade | employmentTitle | employmentLength | homeOwnership | ... | n5 | n6 | n7 | n8 | n9 | n10 | n11 | n12 | n13 | n14 | |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
0 | 0 | 35000.0 | 5 | 19.52 | 917.97 | E | E2 | 320.0 | 2 years | 2 | ... | 9.0 | 8.0 | 4.0 | 12.0 | 2.0 | 7.0 | 0.0 | 0.0 | 0.0 | 2.0 |
1 | 1 | 18000.0 | 5 | 18.49 | 461.90 | D | D2 | 219843.0 | 5 years | 0 | ... | NaN | NaN | NaN | NaN | NaN | 13.0 | NaN | NaN | NaN | NaN |
2 | 2 | 12000.0 | 5 | 16.99 | 298.17 | D | D3 | 31698.0 | 8 years | 0 | ... | 0.0 | 21.0 | 4.0 | 5.0 | 3.0 | 11.0 | 0.0 | 0.0 | 0.0 | 4.0 |
3 | 3 | 11000.0 | 3 | 7.26 | 340.96 | A | A4 | 46854.0 | 10+ years | 1 | ... | 16.0 | 4.0 | 7.0 | 21.0 | 6.0 | 9.0 | 0.0 | 0.0 | 0.0 | 1.0 |
4 | 4 | 3000.0 | 3 | 12.99 | 101.07 | C | C2 | 54.0 | NaN | 1 | ... | 4.0 | 9.0 | 10.0 | 15.0 | 7.0 | 12.0 | 0.0 | 0.0 | 0.0 | 4.0 |
5 rows × 47 columns
数据概况
一般而言,对于数据在比赛界面都有对应的数据概况介绍(匿名特征除外),说明列的性质特征。了解列的性质会有助于我们对于数据的理解和后续分析。 Tip:匿名特征,就是未告知数据列所属的性质的特征列。
train.csv
- id 为贷款清单分配的唯一信用证标识
- loanAmnt 贷款金额
- term 贷款期限(year)
- interestRate 贷款利率
- installment 分期付款金额
- grade 贷款等级
- subGrade 贷款等级之子级
- employmentTitle 就业职称
- employmentLength 就业年限(年)
- homeOwnership 借款人在登记时提供的房屋所有权状况
- annualIncome 年收入
- verificationStatus 验证状态
- issueDate 贷款发放的月份
- purpose 借款人在贷款申请时的贷款用途类别
- postCode 借款人在贷款申请中提供的邮政编码的前3位数字
- regionCode 地区编码
- dti 债务收入比
- delinquency_2years 借款人过去2年信用档案中逾期30天以上的违约事件数
- ficoRangeLow 借款人在贷款发放时的fico所属的下限范围*
- ficoRangeHigh 借款人在贷款发放时的fico所属的上限范围
- openAcc 借款人信用档案中未结信用额度的数量
- pubRec 贬损公共记录的数量
- pubRecBankruptcies 公开记录清除的数量
- revolBal 信贷周转余额合计
- revolUtil 循环额度利用率,或借款人使用的相对于所有可用循环信贷的信贷金额
- totalAcc 借款人信用档案中当前的信用额度总数
- initialListStatus 贷款的初始列表状态
- applicationType 表明贷款是个人申请还是与两个共同借款人的联合申请
- earliesCreditLine 借款人最早报告的信用额度开立的月份
- title 借款人提供的贷款名称
- policyCode 公开可用的策略_代码=1新产品不公开可用的策略_代码=2
n系列匿名特征 匿名特征n0-n14,为一些贷款人行为计数特征的处理
## 混淆矩阵
import numpy as np
from sklearn.metrics import confusion_matrix
y_pred = [0, 1, 0, 1]
y_true = [0, 1, 1, 0]
print('混淆矩阵:\n',confusion_matrix(y_true, y_pred))
混淆矩阵:
[[1 1]
[1 1]]
## accuracy
from sklearn.metrics import accuracy_score
y_pred = [0, 1, 0, 1]
y_true = [0, 1, 1, 0]
print('ACC:',accuracy_score(y_true, y_pred))
ACC: 0.5
## Precision,Recall,F1-score
from sklearn import metrics
y_pred = [0, 1, 0, 1]
y_true = [0, 1, 1, 0]
print('Precision',metrics.precision_score(y_true, y_pred))
print('Recall',metrics.recall_score(y_true, y_pred))
print('F1-score:',metrics.f1_score(y_true, y_pred))
Precision 0.5
Recall 0.5
F1-score: 0.5
## P-R曲线
import matplotlib.pyplot as plt
from sklearn.metrics import precision_recall_curve
y_pred = [0, 1, 1, 0, 1, 1, 0, 1, 1, 1]
y_true = [0, 1, 1, 0, 1, 0, 1, 1, 0, 1]
precision, recall, thresholds = precision_recall_curve(y_true, y_pred)
plt.plot(precision, recall)
[<matplotlib.lines.Line2D at 0x274cd543c50>]
## ROC曲线
from sklearn.metrics import roc_curve
y_pred = [0, 1, 1, 0, 1, 1, 0, 1, 1, 1]
y_true = [0, 1, 1, 0, 1, 0, 1, 1, 0, 1]
FPR,TPR,thresholds=roc_curve(y_true, y_pred)
plt.title('ROC')
plt.plot(FPR, TPR,'b')
plt.plot([0,1],[0,1],'r--')
plt.ylabel('TPR')
plt.xlabel('FPR')
Text(0.5, 0, 'FPR')
## AUC
import numpy as np
from sklearn.metrics import roc_auc_score
y_true = np.array([0, 0, 1, 1])
y_scores = np.array([0.1, 0.4, 0.35, 0.8])
print('AUC socre:',roc_auc_score(y_true, y_scores))
AUC socre: 0.75
## KS值 在实际操作时往往使用ROC曲线配合求出KS值
from sklearn.metrics import roc_curve
y_pred = [0, 1, 1, 0, 1, 1, 0, 1, 1, 1]
y_true = [0, 1, 1, 0, 1, 0, 1, 1, 1, 1]
FPR,TPR,thresholds=roc_curve(y_true, y_pred)
KS=abs(FPR-TPR).max()
print('KS值:',KS)
KS值: 0.5238095238095237
#评分卡 不是标准评分卡
def Score(prob,P0=600,PDO=20,badrate=None,goodrate=None):
P0 = P0
PDO = PDO
theta0 = badrate/goodrate
B = PDO/np.log(2)
A = P0 + B*np.log(2*theta0)
score = A-B*np.log(prob/(1-prob))
return score
此EDA参考:https://github.com/datawhalechina/team-learning-data-mining
完成