Remove all elements from a linked list of integers that have value val.
Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5
思路:操纵链表节点最好的方式当然是双重指针了。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* removeElements(ListNode* head, int val) {
ListNode** tmp = &head;
while(*tmp){
if((*tmp)->val == val) *tmp = (*tmp)->next;
else tmp = &((*tmp)->next);
}
return head;
}
};