LeetCode 191: Number of 1 Bits

除以2取余数，空间复杂度o(1)

class Solution {
public:
    int hammingWeight(uint32_t n) {
        int count=0;
		int i=1;
		
        for(i=1;i<=32;i++)
        {
            count=count+n%2;
			n=n/2;
        }
		return count;
    }
};