[Leetcode By Python]69. Sqrt(x)

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本文介绍了一种求解整数平方根的算法，并通过Python代码实现了该算法。输入为非负整数x，返回其平方根的整数部分。

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题目：

Implement int sqrt(int x).

Compute and return the square root of x.

x is guaranteed to be a non-negative integer.

Example 1:

Input: 4
Output: 2

Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since we want to return an integer, the decimal part will be truncated.

代码＋调试：

class Solution(object):
    def mySqrt(self, x):
        """
        :type x: int
        :rtype: int
        """
        if x==0:
            return 0
        i = 1;j=x/2+1
        while i<=j:
            mid = (i+j)/2
            if mid**2 == x:
                return mid
            elif mid**2>x:
                j = mid-1
            else:
                i = mid+1
        return j

a = Solution()
print a.mySqrt(8)