给你二叉树的根节点 root
,返回其节点值 自底向上的层序遍历 。 (即按从叶子节点所在层到根节点所在的层,逐层从左向右遍历)
示例 1:
输入:root = [3,9,20,null,null,15,7] 输出:[[15,7],[9,20],[3]]
示例 2:
输入:root = [1] 输出:[[1]]
示例 3:
输入:root = [] 输出:[]
package com.company;
import javax.swing.tree.TreeNode;
import java.lang.reflect.Array;
import java.util.*;
public class Main {
public static void main(String[] args) {
TreeNode head = new TreeNode(1);
head.left = new TreeNode(2);
head.right = new TreeNode(3);
head.left.left = new TreeNode(4);
head.left.right = new TreeNode(5);
head.right.left = new TreeNode(6);
head.right.right = new TreeNode(7);
List<List<Integer>> list = levelOrderBottom(head);
}
/**
* 层序遍历(自底向上)(广度优先)
*
* @param root
* @return
*/
public static List<List<Integer>> levelOrderBottom(TreeNode root) {
List<List<Integer>> result = new ArrayList();
Queue<TreeNode> queue = new LinkedList<>();
LinkedList tmp = new LinkedList<>();
if (root != null) {
queue.offer(root);//先放第一个节点
}
while (!queue.isEmpty()) {//整个二叉树
int size = queue.size();//注意要在这里取长度
List<Integer> list = new ArrayList<>();
while (size > 0) {//按层
TreeNode node = queue.peek();//让节点每次往后移动
list.add(queue.poll().val);//队列里弹出值
if (node.left != null) {//加入左边的值
queue.offer(node.left);
}
if (node.right != null) {//加入右边的值
queue.offer(node.right);
}
size = size - 1;//数量减少1
}
tmp.addFirst(list);
}
for (int i = 0; i < tmp.size(); i++) {
result.add((List<Integer>) tmp.get(i));
}
return result;
}
static class TreeNode {
int val;
TreeNode left;
TreeNode right;
public TreeNode(int val) {
this.val = val;
}
}
}