检查外键是否有索引的SQL_查表里有没有外键索引-优快云博客

本文提供了一段用于检查Oracle数据库中外键约束是否拥有对应索引的SQL语句，通过解析外键列并对比索引，帮助数据库管理员或开发者确保数据库性能与数据一致性。

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经常用到Oracle中检查外键是否有索引的SQL，这里记录下，以备不时之需

SELECT OWNER,
      TABLE_NAME,
        CONSTRAINT_NAME,
        CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
        NVL2(CNAME3, ',' || CNAME3, NULL) ||
        NVL2(CNAME4, ',' || CNAME4, NULL) ||
        NVL2(CNAME5, ',' || CNAME5, NULL) ||
        NVL2(CNAME6, ',' || CNAME6, NULL) ||
        NVL2(CNAME7, ',' || CNAME7, NULL) ||
        NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
   FROM (SELECT B.OWNER,B.TABLE_NAME,
                B.CONSTRAINT_NAME,
                MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
                MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
                MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
                MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
                MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
                MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
                MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
                MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
                COUNT(*) COL_CNT
           FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
                        SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
                        SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
                        POSITION
                   FROM DBA_CONS_COLUMNS WHERE OWNER NOT IN ('SYS','SYSTEM','SYSMAN','HR','OE','EXFSYS','DBSNMP','MDSYS','OLAPSYS','SCOTT','EXFSYS','SH','PM','CTXSYS')) A,
                DBA_CONSTRAINTS B
          WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
            AND B.CONSTRAINT_TYPE = 'R'
          GROUP BY B.OWNER,B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
WHERE COL_CNT > ALL
(SELECT COUNT(*)
           FROM DBA_IND_COLUMNS I
          WHERE I.TABLE_NAME = CONS.TABLE_NAME AND I.TABLE_OWNER=CONS.OWNER
            AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
                 CNAME6, CNAME7, CNAME8)
            AND I.COLUMN_POSITION <= CONS.COL_CNT
          GROUP BY I.INDEX_NAME) order by name ;