题目
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
把两个排序的链表合并起来。
1 合并排序的一部分,基础的基础。
2 当一个链表结束的时候,后续部分不要写错。
if(l1==null){
cur3.next = l2; //不是l1
}
public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode dummy = new ListNode(Integer.MIN_VALUE);
ListNode cur3 = dummy;
while(l1!=null && l2!=null){
if(l1.val<l2.val){
cur3.next = l1;
cur3 = cur3.next;
l1 = l1.next;
}
else{
cur3.next = l2;
cur3 = cur3.next;
l2 = l2.next;
}
}
if(l1==null){
cur3.next = l2;
}
else{
cur3.next = l1;
}
return dummy.next;
}
}
&& 与 || 要注意