任务三:在方案二的基础上,扩展+、-、*、/运算符的功能,使之能与double型数据进行运算。设Complex c; double d; c?d和d?c的结果为“将d视为实部为d的复数同c运算”的结果(其中?为+、-、*、/之一)。另外,再定义一目运算符 -,-c相当于0-c。
/*
* 程序的版权和版本声明部分
* Copyright (c)2013, 烟台大学计算机学院学生
* All rightsreserved.
* 文件名称:score.cpp
* 作 者: 王昕彤
* 完成日期: 2013 年 4月 22日
* 版本号: v1.0
* 输入描述:
* 问题描述:
* 输出:
*/
#include<iostream>
using namespace std;
class Complex
{
public:
Complex()
{
real=0;
imag=0;
}
Complex(double r,double i)
{
real=r;
imag=i;
}
friend Complex operator+(double c1,Complex &c2);
friend Complex operator-(double c1,Complex &c2);
friend Complex operator*(double c1,Complex &c2);
friend Complex operator/(double c1,Complex &c2);
void display();
private:
double real;
double imag;
};
Complex operator +(double c1,Complex &c2)
{
return Complex(c1+c2.real,c2.imag);
}
Complex operator -(double c1,Complex &c2)
{
return Complex(c1-c2.real,c2.imag);
}
Complex operator *(double c1,Complex &c2)
{
return Complex(c1*c2.real,c2.imag);
}
Complex operator /(double c1,Complex &c2)
{
return Complex(c1/c2.real,c2.imag);
}
void Complex::display()
{
if(imag>0)
{
cout<<real<<"+"<<imag<<"i"<<endl;
}
else if(imag==0)
{
cout<<real<<endl;
}
else if(imag<0)
{
cout<<real<<imag<<"i"<<endl;
}
}
int main()
{
Complex c1,c2(5,-10),c3;
cout<<"c1=";
c1.display();
cout<<"c2=";
c2.display();
c3=1.3+c2;
cout<<"c1+c2=";
c3.display();
c3=2.4-c2;
cout<<"c1-c2=";
c3.display();
c3=1.5*c2;
cout<<"c1*c2=";
c3.display();
c3=10.0/c2;
cout<<"c1/c2=";
c3.display();
return 0;
}
运行结果: