A + B Again HDU - 2057

最新推荐文章于 2020-04-05 20:01:56 发布

原创最新推荐文章于 2020-04-05 20:01:56 发布 · 242 阅读

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本文介绍了一个简单的十六进制整数加法程序，该程序能够接收两个十六进制整数作为输入，并输出它们的和。文章提供了完整的C语言源代码实现，包括如何处理负数的十六进制表示。

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

InputThe input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.OutputFor each test case,print the sum of A and B in hexadecimal in one line.
Sample Input

+A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output

0
2C
11
-2C
-90

#include <stdio.h>
#include <string.h>
#define MAX 100

int main()
{
    long long n,m,v;
    while(scanf("%llx%llx",&n,&m)==2)
    {
        v=n+m;
        if(v<0)
        {
            v=-v;
            printf("-%llX\n",v);
        }
        else
        printf("%llX\n",v);
    }
     return 0;
 }