aardio - 将稀疏数组变为有序数组

import console; 

var t = {
    [11]={id=11;classId=3;name="张三"};
    [4]={id=4;classId=3;name="张三"};
    [1]={id=1;classId=3;name="张三"};
    [99999999]={id=99999999;classId=3;name="张三"};
    [2]={id=2;classId=3;name="张三"};
    strkey9 = "str999999";
    strkey1 = "str111111";  
}
console.dump("原稀疏数组：",t,"#t获取的成员数：",#t,'\n\n')

var ts = time.tick()
var s,a,b = {},table.range(t);
for(i=a;b;1){
    if t[i]!==null {
        table.push(s,t[i])
    }
}
ts = time.tick()-ts
console.dump("生成一个有序数组(忽略字典成员)：",s,"#t获取的成员数：",#s,"耗时：",ts,'\n\n')

var ts = time.tick();
var keys,result={},{};
for(k,v in t){
    if type(k)==="number" ..table.push(keys,k);
}
..table.sort(keys);
for(i=1;#keys;1){
    ..table.push(result,t[keys[i]]);
}
ts = time.tick()-ts
console.dump("生成一个有序数组(忽略字典成员)：",result,"#t获取的成员数：",#result,"耗时：",ts,'\n\n')

console.pause();