Triangle

1.题目:

A - Triangle
Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u
Submit
 
Status
 
Practice
 
CodeForces 6A
Description
Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allowed to break the sticks or use their partial length. Anne has perfectly solved this task, now she is asking Johnny to do the same.

The boy answered that he would cope with it without any difficulty. However, after a while he found out that different tricky things can occur. It can happen that it is impossible to construct a triangle of a positive area, but it is possible to construct a degenerate triangle. It can be so, that it is impossible to construct a degenerate triangle even. As Johnny is very lazy, he does not want to consider such a big amount of cases, he asks you to help him.

Input
The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks.

Output
Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the sticks or use their partial length.

Sample Input
Input
4 2 1 3
Output
TRIANGLE
Input
7 2 2 4
Output
SEGMENT
Input
3 5 9 1
Output
IMPOSSIBLE
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Anything about the OJ, please ask in the forum, or contact author:Isun
Server Time: 2012-12-05 21:27:09


 

2,题意:

给定四个数,选3个数看能否构成三角形,能输出

TRIANGLE
若不能输出impossible
若有两个数之和等于第三个数,输出segment

 

3.代码:

#include<stdio.h>
#include<algorithm>
using namespace std;
int a[4];
int cmp(int b,int c)
{
    return b>c;
}
int main()
{

        for(int i=0; i<4; i++)
        {
            scanf("%d",&a[i]);
        }
        sort(a,a+4,cmp);
        if(((a[1]+a[2]>a[0])&&(a[0]-a[2])<a[1])||(a[2]+a[3]>a[1])&&(a[1]-a[3]<a[2]))
            printf("TRIANGLE\n");
            else if((a[3]+a[2]==a[1])||(a[1]+a[2]==a[0]))
                printf("SEGMENT\n");
                else
                    printf("IMPOSSIBLE\n");

    return 0;
}


 

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