http://codeforces.com/problemset/problem/4/A

当两位朋友买了一个最大的、最成熟的水蜜桃,他们想要公平地分成两份,每份重量都是偶数公斤。本文探讨了如何通过数学方法解决这个问题,确保每个朋友都能得到他们渴望的、偶数公斤的水蜜桃。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

A. Watermelon
time limit per test
1 second
memory limit per test
64 megabytes
input
standard input
output
standard output

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

Input

The first (and the only) input line contains integer number w (1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.

Output

Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.

Sample test(s)
Input
8
Output
YES


#include<iostream>
#include<stdio.h>
using namespace std;
int main()
{
    int n;
    scanf("%d",&n);
    if(n!=2&&n%2==0)
    printf("YES\n");
    else printf("NO\n");
    return 0;
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值