[LeetCode 316] Remove Duplicate Letters

最新推荐文章于 2020-10-12 16:15:00 发布

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最新推荐文章于 2020-10-12 16:15:00 发布

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分类专栏： Leetcode Java 文章标签： leetcode gready

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本文介绍了一种算法，用于从仅包含小写字母的字符串中移除所有重复的字符，确保每个字母只出现一次，并保持结果字符串在字典序上尽可能最小。通过一个递归函数实现该算法。

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Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results.

Example:

Given "bcabc"
Return "abc"

Given "cbacdcbc"
Return "acdb"

Solution: reference

After determining the greedy choice s[i], we get a new string s' from s by

removing all letters to the left of s[i],
removing all s[i]'s from s.

public String removeDuplicateLetters(String s) {
        int[] count = new int[26];
        int pos = 0;
        for(int i=0; i<s.length(); i++) count[s.charAt(i) - 'a']++;
        for(int i=0; i<s.length(); i++) {
            if(s.charAt(i)< s.charAt(pos)) pos = i;
            if(--count[s.charAt(i) - 'a'] == 0) break;
        }
        return s.length() == 0? "" : s.charAt(pos) + removeDuplicateLetters(s.substring(pos+1).replaceAll(""+ s.charAt(pos), ""));
    }