Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
1. every time n&1, until n==0.
2. n&(n-1) will remove last 1 digit in n, use this to count how many 1 in the number
public int hammingWeight(int n) {
int count = 0;
while(n!=0){
n = (n-1) & n;
count++;
}
return count;
}
计算整数的二进制1位数量:汉明重量

本文提供了一个函数,用于计算给定无符号整数的二进制表示中1的数量,即汉明重量。通过循环与操作和移位操作来实现这一目标。
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