ZOJ 1082 dijkstra 最短路径

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <limits.h>
#include <memory.h>
#define MAX 1010
#define INF 10000
int n;
int data[MAX][MAX];
int cal[MAX];
int used[MAX];
int lowcost[MAX];
int dijkstra( int start )
{
	memset(used, 0, sizeof(used) );
	int max = 0, choose, temp, i, j;
	for( i = 1; i <= n; i++ )
		lowcost[i] = data[start][i];
	lowcost[start] = 0;
	used[start] = 1;
	for( i = 1; i <= n-1; i++ )
	{
	        temp = INF;
		for( j = 1; j <= n; j++ )
		{
			if( !used[j] && lowcost[j] <= temp )
				temp = lowcost[choose=j];
		}
		used[choose] = 1;
		for( j = 1; j <= n; j++ )
		{
			if( !used[j] &&	lowcost[choose] + data[choose][j] < lowcost[j] )
				lowcost[j] = lowcost[choose] + data[choose][j];
		}
	}
	for( j = 1; j <= n; j++ )
	{
		if( lowcost[j] > max )
			max = lowcost[j];
	}
	return max;			
}
int main()
{
	int flag, m, min, t, time, x, i, j;
	while( scanf( "%d", &n ) && n )
	{
		for( i = 1; i <= n; i++ )
			for( j = 1; j <= n; j++ )
				data[i][j] = INF;
		for( i = 1; i <= n; i++ )
		{
			scanf( "%d", &t );
			while( t-- )
			{
				scanf( "%d%d", &x, &time );
				data[i][x] = time;	
			}
		}
	
		for( i = 1; i <= n; i++ )
			cal[i] = dijkstra( i );
		min = 999999;
		flag = 0;
		for( i = 1; i <= n; i++ )
		{
			if( cal[i] < min )
			{
				min = cal[i];
				m = i;
			}
			if( cal[i] != INF )
				flag = 1;
		}
		if( flag )
		{
			printf( "%d %d\n", m, min );
		}
		else
			printf( "disjoint\n" );
	}
	return 0;
}


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