Python计算10000以下的Lychrel数个数

#获取回文数
def GetHuiWen(num):
    numFanZhuan= int(str(num)[::-1])#反转字符串
    return numFanZhuan
#加上回文数
def addHuiWen(num):
    return num+numFanZhuan
#判断是否为回文
def isHuiwen(num):
    if num==GetHuiWen(num):
        return True
    else:
        return False
#判断是否为Lychrel,count为获取回文次数
def isLychrel(num,count):
    while count>=0:
        num=num+GetHuiWen(num)
        if isHuiwen(num):
            return False
        else:
            count=count-1
    return True
count=0

for value in range(10000):
    if isLychrel(value,50):
        #print (value)
        count+=1
print (count)

此问题好像是欧拉计划里面的题目