[Leetcode] Remove Duplicates from Sorted Array

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn't matter what you leave beyond the new length.

两种方法：

int removeDuplicates(int* nums, int numsSize) 
{
/*
	int i = 0;
	int j = 0;
	
	for(j = 0; j < numsSize ; j ++){
		if (j + 1 < numsSize && nums[j] != nums[j + 1]){
			nums[i] = nums[j];
			i ++;			
		}
		else if(j + 1 == numsSize){
			nums[i] = nums[j];
			i ++;
		}
	}
	
	return i;*/	
	
    if (numsSize == 0) return 0;
    
	int i = 0;
    int j ;
    
	for (j = 1; j < numsSize; j++) {
        if (nums[j] != nums[i]) {
            i++;
            nums[i] = nums[j];
        }
    }
    
    return i + 1;	
}

注：两个索引，一个用于访问，一个用于新生成的数组索引