https://blog.youkuaiyun.com/b695886658/article/details/80856080?utm_medium=distribute.pc_relevant.none-task-blog-2defaultbaidujs_baidulandingword~default-0.essearch_pc_relevant&spm=1001.2101.3001.4242.1
- 找到图像1和图像2中最强的匹配点所在的位置
- 通过映射矩阵变换,得到图像1的最强匹配点经过映射后投影到新图像上的位置坐标
- 在新图像上的最强匹配点的映射坐标处,衔接两幅图像,该点左侧图像完全是图像1,右侧完全是图像2
#include "highgui/highgui.hpp"
#include "opencv2/nonfree/nonfree.hpp"
#include "opencv2/legacy/legacy.hpp"
using namespace cv;
//计算原始图像点位在经过矩阵变换后在目标图像上对应位置
Point2f getTransformPoint(const Point2f originalPoint,const Mat &transformMaxtri);
int main(int argc,char *argv[])
{
Mat image01=imread(argv[1]);
Mat image02=imread(argv[2]);
imshow("拼接图像1",image01);
imshow("拼接图像2",image02);
//灰度图转换
Mat image1,image2;
cvtColor(image01,image1,CV_RGB2GRAY);
cvtColor(image02,image2,CV_RGB2GRAY);
//提取特征点
SiftFeatureDetector siftDetector(800); // 海塞矩阵阈值 //编译报错,不能用,申请了专利,不提供此api了
vector<KeyPoint> keyPoint1,keyPoint2;
siftDetector.detect(image1,keyPoint1);
siftDetector.detect(image2,keyPoint2);
//特征点描述,为下边的特征点匹配做准备
SiftDescriptorExtractor siftDescriptor;
Mat imageDesc1,imageDesc2;
siftDescriptor.compute(image1,keyPoint1,imageDesc1);
siftDescriptor.compute(image2,keyPoint2,imageDesc2);
//获得匹配特征点,并提取最优配对
FlannBasedMatcher matcher;
vector<DMatch> matchePoints;
matcher.match(imageDesc1,imageDesc2,matchePoints,Mat());
sort(matchePoints.begin(),matchePoints.end()); //特征点排序
//获取排在前N个的最优匹配特征点
vector<Point2f> imagePoints1,imagePoints2;
for(int i=0;i<10;i++)
{
imagePoints1.push_back(keyPoint1[matchePoints[i].queryIdx].pt);
imagePoints2.push_back(keyPoint2[matchePoints[i].trainIdx].pt);
}
//获取图像1到图像2的投影映射矩阵,尺寸为3*3
Mat homo=findHomography(imagePoints1,imagePoints2,CV_RANSAC);
Mat adjustMat=(Mat_<double>(3,3)<<1.0,0,image01.cols,0,1.0,0,0,0,1.0);
Mat adjustHomo=adjustMat*homo;
//获取最强配对点在原始图像和矩阵变换后图像上的对应位置,用于图像拼接点的定位
Point2f originalLinkPoint,targetLinkPoint,basedImagePoint;
originalLinkPoint=keyPoint1[matchePoints[0].queryIdx].pt;
targetLinkPoint=getTransformPoint(originalLinkPoint,adjustHomo);
basedImagePoint=keyPoint2[matchePoints[0].trainIdx].pt;
//图像配准
Mat imageTransform1;
warpPerspective(image01,imageTransform1,adjustMat*homo,Size(image02.cols+image01.cols+110,image02.rows));
//在最强匹配点左侧的重叠区域进行累加,是衔接稳定过渡,消除突变
Mat image1Overlap,image2Overlap; //图1和图2的重叠部分
image1Overlap=imageTransform1(Rect(Point(targetLinkPoint.x-basedImagePoint.x,0),Point(targetLinkPoint.x,image02.rows)));
image2Overlap=image02(Rect(0,0,image1Overlap.cols,image1Overlap.rows));
Mat image1ROICopy=image1Overlap.clone(); //复制一份图1的重叠部分
for(int i=0;i<image1Overlap.rows;i++)
{
for(int j=0;j<image1Overlap.cols;j++)
{
double weight;
weight=(double)j/image1Overlap.cols; //随距离改变而改变的叠加系数
image1Overlap.at<Vec3b>(i,j)[0]=(1-weight)*image1ROICopy.at<Vec3b>(i,j)[0]+weight*image2Overlap.at<Vec3b>(i,j)[0];
image1Overlap.at<Vec3b>(i,j)[1]=(1-weight)*image1ROICopy.at<Vec3b>(i,j)[1]+weight*image2Overlap.at<Vec3b>(i,j)[1];
image1Overlap.at<Vec3b>(i,j)[2]=(1-weight)*image1ROICopy.at<Vec3b>(i,j)[2]+weight*image2Overlap.at<Vec3b>(i,j)[2];
}
}
Mat ROIMat=image02(Rect(Point(image1Overlap.cols,0),Point(image02.cols,image02.rows))); //图2中不重合的部分
ROIMat.copyTo(Mat(imageTransform1,Rect(targetLinkPoint.x,0, ROIMat.cols,image02.rows))); //不重合的部分直接衔接上去
namedWindow("拼接结果",0);
imshow("拼接结果",imageTransform1);
imwrite("D:\\拼接结果.jpg",imageTransform1);
waitKey();
return 0;
}
//计算原始图像点位在经过矩阵变换后在目标图像上对应位置
Point2f getTransformPoint(const Point2f originalPoint,const Mat &transformMaxtri)
{
Mat originelP,targetP;
originelP=(Mat_<double>(3,1)<<originalPoint.x,originalPoint.y,1.0);
targetP=transformMaxtri*originelP;
float x=targetP.at<double>(0,0)/targetP.at<double>(2,0);
float y=targetP.at<double>(1,0)/targetP.at<double>(2,0);
return Point2f(x,y);
}
测试用例三原图1:
测试用例三原图2:
处理后结果