用ruby找出1到N之间的质数

a = Array.new
def find(n,a)
  (2..n).each{|n|
     x = 0
     (2...n).each{|i|
       if n%i == 0
         x = 1
         break
       end
     }
     if x == 0
       a << n
     end
  }
end

find(10000,a)

a.each{|a|
  print a,"\n"
}