CodeForces - 731C

本文介绍了一个有趣的问题:如何通过最少的颜色更改使每天穿着相同颜色的袜子成为可能。使用并查集算法,我们解决了母亲为儿子留下的混乱袜子搭配指令,确保了每双袜子在指定天数内颜色一致。

Problem
Arseniy is already grown-up and independent. His mother decided to leave him alone for m days and left on a vacation. She have prepared a lot of food, left some money and washed all Arseniy’s clothes.

Ten minutes before her leave she realized that it would be also useful to prepare instruction of which particular clothes to wear on each of the days she will be absent. Arseniy’s family is a bit weird so all the clothes is enumerated. For example, each of Arseniy’s n socks is assigned a unique integer from 1 to n. Thus, the only thing his mother had to do was to write down two integers l i and r i for each of the days — the indices of socks to wear on the day i (obviously, l i stands for the left foot and r i for the right). Each sock is painted in one of k colors.

When mother already left Arseniy noticed that according to instruction he would wear the socks of different colors on some days. Of course, that is a terrible mistake cause by a rush. Arseniy is a smart boy, and, by some magical coincidence, he posses k jars with the paint — one for each of k colors.

Arseniy wants to repaint some of the socks in such a way, that for each of m days he can follow the mother’s instructions and wear the socks of the same color. As he is going to be very busy these days he will have no time to change the colors of any socks so he has to finalize the colors now.

The new computer game Bota-3 was just realised and Arseniy can’t wait to play it. What is the minimum number of socks that need their color to be changed in order to make it possible to follow mother’s instructions and wear the socks of the same color during each of m days.

Input
The first line of input contains three integers n, m and k (2 ≤ n ≤ 200 000, 0 ≤ m ≤ 200 000, 1 ≤ k ≤ 200 000) — the number of socks, the number of days and the number of available colors respectively.

The second line contain n integers c 1, c 2, …, c n (1 ≤ c i ≤ k) — current colors of Arseniy’s socks.

Each of the following m lines contains two integers l i and r i (1 ≤ l i, r i ≤ n, l i ≠ r i) — indices of socks which Arseniy should wear during the i-th day.

Output
Print one integer — the minimum number of socks that should have their colors changed in order to be able to obey the instructions and not make people laugh from watching the socks of different colors.

并查集
AC代码:

#include<iostream>
#include<vector>
#include<algorithm>
#include<map>
using namespace std;
int co[200005], father[2000005], num[200005];
int n, m, k, x, y;
vector<int>p[200005];
int find(int x)
{
	if (father[x] != x)
	{
	
		father[x] = find(father[x]);
	}
	return father[x];
}
int main()
{
	cin >> n >> m >> k;
	for (int i = 1; i <= n; i++)
	{
	
		father[i] = i;
		cin >> co[i];
	}
	for (int i = 1; i <= m; i++)
	{
	
		cin >> x >> y;
		int px = find(x);
		int py = find(y);
		if (px != py)
			father[px] = father[py];
	}
	for (int i = 1; i <= n; i++)
	{
	
		int px = find(i);
		p[px].push_back(co[i]);
	}
	int ans = 0, maxn;
	for (int i = 1; i <= n; i++)
	{
	
		if (p[i].size() == 1)
			continue;
		map<int, int>rema;
		maxn = 0;
		for (int j = 0; j < p[i].size(); j++)
		{
		
			rema[p[i][j]]++;
			maxn = max(maxn, rema[p[i][j]]);
		}
		ans += p[i].size() - maxn;
	}
	cout << ans << endl;
}
评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
红包 添加红包
表情包 插入表情
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值