226. Invert Binary Tree

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本文介绍了一种翻转二叉树的算法实现，通过递归方式交换每个节点的左右子节点来完成整个二叉树的翻转。该算法简单高效，易于理解和实现。


/*
Invert a binary tree.

     4
   /   \
  2     7
 / \   / \
1   3 6   9
to
     4
   /   \
  7     2
 / \   / \
9   6 3   1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), 
but you can’t invert a binary tree on a whiteboard so fuck off.
*/


/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* invertTree(TreeNode* root) {
        if(!root) return root;
        TreeNode* tmp=root->left;
        root->left=root->right;
        root->right=tmp;
        invertTree(root->left);
        invertTree(root->right);
        return root;
    }
};