<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[qq_73793166的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/qq_73793166</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; qq_73793166]]></copyright><item><title><![CDATA[Redis Stream 入门]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/146739234</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/146739234</guid><author>qq_73793166</author><pubDate>Sun, 30 Mar 2025 11:58:27 +0800</pubDate><description><![CDATA[Redis Stream新手向理解。]]></description><category></category></item><item><title><![CDATA[通过 Docker 安装 iTop —— 快速搭建 IT 服务管理平台]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/144409459</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/144409459</guid><author>qq_73793166</author><pubDate>Wed, 11 Dec 2024 20:37:29 +0800</pubDate><description><![CDATA[通过 Docker 安装 iTop —— 快速搭建 IT 服务管理平台]]></description><category></category></item><item><title><![CDATA[Jmeter使用教程(以登录后获取token进行测试为例)]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/144405910</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/144405910</guid><author>qq_73793166</author><pubDate>Wed, 11 Dec 2024 17:24:41 +0800</pubDate><description><![CDATA[Jmeter使用教程(以登录后获取token进行测试为例)]]></description><category></category></item><item><title><![CDATA[如何在Spring Boot中调用WebService开放接口：国内航班查询案例]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/144191575</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/144191575</guid><author>qq_73793166</author><pubDate>Mon, 02 Dec 2024 16:34:52 +0800</pubDate><description><![CDATA[在现代应用开发中，许多系统需要通过调用外部WebService来获取数据并进行处理。WebService提供了一种标准的通信方式，允许不同系统之间的互操作。本文将通过一个Spring Boot示例，演示如何调用国内航班WebService来查询航班信息，并将结果封装成自己的API接口。]]></description><category></category></item><item><title><![CDATA[如何在 Spring Boot 项目中集成七牛云存储]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/144186396</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/144186396</guid><author>qq_73793166</author><pubDate>Mon, 02 Dec 2024 13:47:37 +0800</pubDate><description><![CDATA[在SpringBoot项目中集成七牛云]]></description><category></category></item><item><title><![CDATA[Next.js路由布局机制详解]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/144174318</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/144174318</guid><author>qq_73793166</author><pubDate>Sun, 01 Dec 2024 20:22:03 +0800</pubDate><description><![CDATA[Next.js新手路由布局机制解析]]></description><category></category></item><item><title><![CDATA[WSL内存占用量大的解决方案]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/144142341</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/144142341</guid><author>qq_73793166</author><pubDate>Fri, 29 Nov 2024 17:33:09 +0800</pubDate><description><![CDATA[解决wsl内存占用过大的问题]]></description><category></category></item><item><title><![CDATA[Docker Desktop使用教程]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/144066021</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/144066021</guid><author>qq_73793166</author><pubDate>Tue, 26 Nov 2024 19:10:32 +0800</pubDate><description><![CDATA[wsl2 Ubuntu新手必看 ]]></description><category></category></item><item><title><![CDATA[SSM起步配置文件(spring6 + JDK17)]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/140560976</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/140560976</guid><author>qq_73793166</author><pubDate>Fri, 19 Jul 2024 22:50:46 +0800</pubDate><description><![CDATA[新手向最新ssm配置]]></description><category></category></item><item><title><![CDATA[Codeforces Round 890 (Div. 2) supported by Constructor Institute ABCD]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/132130566</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/132130566</guid><author>qq_73793166</author><pubDate>Sun, 06 Aug 2023 14:30:50 +0800</pubDate><description><![CDATA[令f(l,r)为区间[l,r]上最大的数，inv(l,r)为区间[l,r]上的逆序数,如果inv(l,r)==inv(l,r-1),则有f(l,r)=r,只有之前区间加上的数是该区间最的大的数才能不影响之前的区间的逆序数，我们可以通过分治，先从只有一个数的区间开始，然后开始合并，每个区间的状态都由其最大值表示，最终一定可以得到f(1,n)统计1的数量cnt和大于1的数的总和sum，只要满足sum>=2*cnt即可，只有出现1补不上了或者n==1才判no；]]></description><category></category></item><item><title><![CDATA[1808B - Playing in a Casino]]></title><link>https://blog.youkuaiyun.com/qq_73793166/article/details/130976060</link><guid>https://blog.youkuaiyun.com/qq_73793166/article/details/130976060</guid><author>qq_73793166</author><pubDate>Wed, 31 May 2023 20:26:59 +0800</pubDate><description><![CDATA[很显然，此时能得到一个规律就是对于其中的每个数，它与排在它后面的数的绝对值差的和可以表示成为 后缀sum-a[i]*(n-j-1)(i从0开始递增），又因为所有的后缀sum的和=a[0]*0+a[1]*1+...........+a[n-1]*(n-1),所以直接扫一遍即可得到结果，每次加上a[i]*j-a[i]*(n-j-1)(再合并一下就是(a[i]*(1+2*j-n)即可，加上sort总复杂度为o(mnlogn）。很显然，如果都是大数减去小数，那么绝对值是可以去掉的。acm小白首篇题解就结束辣！]]></description><category></category></item></channel></rss>