摘要: 以往我们都是肯定绞尽脑汁,肯定什么循环,元素⼤⼩,什么因素都考虑进去。但是现在采⽤Linq可
以很好的解决这个问题。找出两个或多个数组的相同项。代码如下:
1 usingSystem;
2 usingSystem.Collections.Generic;
3 usingSystem.Linq;
4 usingSystem.Text;
5 namespaceTest4_03
6 {
7 classProgram
8 {
9 staticvoidMain(string[] args)
10 {
11 string[] names = {"Adams","Arthur","Buchanan","Tsbuch
is","ShCian","FuchsiaLinda","DecheChen","Lotheer","FindLanciCad
e",
12 "SorchLand","JiangZheng","MisiiLoda","Gtod","Dfac","L
ama","BakCades","Losangle","ZheWQ","GehengDahaLothi","ToryLande
y",
13 "DakaLothy","BthLanda","MenNorth","Fith","FoxMain","D
ontM","Saobba","Del","Sala","Ghero","BhthLaPhda"};
14 IEnumerable<string> skip = names.Skip(10);
15 IEnumerable<string> take = names.Take(11);
16 //取出两个序列中交集部分,按理论应该输出JiangZheng
17 IEnumerable<string> intersect = skip.Intersect(take);
18 foreach(varsinintersect)
19 {
20 Console.WriteLine(s);
21 }
22 Console.ReadKey();
23 }
24 }
25 }