C++24点游戏

最新推荐文章于 2025-06-20 10:06:32 发布

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最新推荐文章于 2025-06-20 10:06:32 发布 · 956 阅读

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#c++ #游戏 #算法

24点游戏的代码，支持界面，排行榜查询，答错纠错，no命令，有隐藏bug哦（算是小彩蛋）看不懂评论区问吧，有时间会解答，急就私戳吧

#include<iostream>
#include<iomanip>
#include<cstdlib>
#include <stdlib.h>
#include <stdio.h>
#include<ctime>
#include <string>
#include <stack>
#include <fstream>
#include <cassert>
using namespace std;
int allnumber[10] = { 1,2,3,4,5,6,7,8,9,10};
int score = 0;
double result;
char card[] = { '1','2','3','4','5','6','7','8','9','0' };
char pai[4] = { '@','@','@','@' };//对牌初始化 
double nums[4];
char ope[4] = { '+','-','*','/' };
void GetCards(int a[])
{
	for (int i = 0; i < 4; i++) {
		pai[i] = '@';
	}
	while (pai[0] == '@' || pai[1] == '@' || pai[2] == '@' || pai[3] == '@')//若牌没有输入，则重新输入 
	{
		int i = 0;
		int j;
		for (i = 0; i < 4; i++)
		{
			j = a[i];
			pai[i] = card[j];
		}
		for (i = 0; i < 4; i++)
		{
			if (pai[i] == '1')  nums[i] = 1;
			if (pai[i] == '2')  nums[i] = 2;
			if (pai[i] == '3')  nums[i] = 3;
			if (pai[i] == '4')  nums[i] = 4;
			if (pai[i] == '5')  nums[i] = 5;
			if (pai[i] == '6')  nums[i] = 6;
			if (pai[i] == '7')  nums[i] = 7;
			if (pai[i] == '8')  nums[i] = 8;
			if (pai[i] == '9')  nums[i] = 9;
			if (pai[i] == '9')  nums[i] = 9;
			if (pai[i] == '0') nums[i] = 10;
		}
	}

	cout << "            随机获得的4张牌为" << nums[0] << "," << nums[1] << "," << nums[2] << "," << nums[3] << "," << endl;
}
double calculate(double a, double b, char op)
{
	if (op == '+') return a + b;
	if (op == '-') return a - b;
	if (op == '*') return a * b;
	if ((op == '/') && (b != 0)) return a / b;
}
int qiongju()
{
	double  temp[3], tem[2];//第一个符号放置后，经过计算后相当于剩下三个数，这个数组用于存储这三个数  
	double  sum;//求得的和  
	int  judge = 0;   //判断是否找到一个合理的解   
	for (int i = 0; i < 4; i++)//第一次放置的符号  
	{
		for (int j = 0; j < 4; j++)   //第二次放置的符号   
		{
			for (int k = 0; k < 4; k++)    //第三次放置的符号    
			{
				for (int m = 0; m < 3; m++)      //首先计算的两个相邻数字，共有3种情况，相当于括号的作用     
				{
					if (nums[m + 1] == 0 && ope[i] == '/') break;
					temp[m] = calculate(nums[m], nums[m + 1], ope[i]);
					temp[(m + 1) % 3] = nu