jsp通过url传值到servlet

最新推荐文章于 2021-02-16 08:24:49 发布

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最新推荐文章于 2021-02-16 08:24:49 发布

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分类专栏： java前端

本文链接：https://blog.youkuaiyun.com/qq_45232054/article/details/103639473

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本文介绍了一个使用JSP页面向Servlet通过URL传递参数的示例，包括JSP页面的编写、Servlet的处理以及参数的接收和打印过程。

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jsp-------->servlet (url)
jsp部分

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>通过url传值</title>
</head>
<body>
<!-- <input type="hidden" name="op" value="urlTovalue"> -->
<!-- 自动获取项目名称 -->
<a href="${pageContext.request.contextPath}/MyServlet?name=xiaoming&password=1234">走</a>
 <!-- 没有自动获取项目名称 -->
<a href="MyServlet?name=xiaoming&password=1234&age=18&sex=2">走ni</a>
</body>
</html>

servlet部分

package com.zparkep.servlet;

import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

@WebServlet("/MyServlet")
public class MyServlet extends HttpServlet {
	private static final long serialVersionUID = 1L;

	public MyServlet() {
		super();
	}

	protected void doGet(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		doPost(request, response);
	}

	protected void doPost(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {


		String name1 = request.getParameter("name");
		String password = request.getParameter("password");
		String age = request.getParameter("age");
		String sex = request.getParameter("sex");

		System.out.println(name1);
		System.out.println(password);
		System.out.println(age);
		System.out.println(sex);
	
	}
}

结果

信息: Server startup in [8,088] milliseconds
xiaoming
1234
18
2