leetcode7 整数反转

7. 整数反转

C语言

int reverse(int x) {
	long int num = 0; //定义为long,防止num到达边界*10后溢出
	while (x)
	{
		num = num * 10 + x % 10;
		if (num > INT_MAX || num < INT_MIN)//判断是否溢出，溢出返回0
			return 0;
		x = x / 10;
	}
	return num;
}