第一期 第八题

A + B Problem Too

Problem Description
This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.

Input
Each line will contain two integers A and B. Process to end of file.

Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.

Sample Input
1 1
8600 8600

Sample Output
no
yes

问难链接：https://vjudge.net/problem/HDU-2101

问题简述：计算A+B，并判断（A+B）% 86 是否为零，是则输出yes，否则输出no；

问题分析：输入整型数A，B，判断A+B对86求余是否为零；

程序说明：利用while循环进行A+B的计算，每次计算都用if语句判断一次（A+B）% 86是否为零；

AC通过的C++语言程序如下：
#include
using namespace std;
int main()
{
int A,B,C;
while(cin>>A>>B)
{
C=A+B;
if(C%86==0) cout<<“yes”<<endl;
else cout<<“no”<<endl;
}
}