mysql> show grants for query_all@'115.236.1x0.x';+-----------------------------------------------------------------------------------------------------------------------+| Grants for query_all@115.236.1x0.x |+-----------------------------------------------------------------------------------------------------------------------+| GRANT USAGE ON *.* TO 'query_all'@'115.236.1x0.x' IDENTIFIED BY PASSWORD '*17167D048E538ED16DF5BD732EF9E1B2D9048F6E' || GRANT SELECT, EXECUTE ON `zjzc`.* TO 'query_all'@'115.236.1x0.x' GRANT USAGE ON *.* TO 'query_all'@'%' identified by '1234567';GRANT SELECT ON `zjzc`.* TO 'query_all'@'%';这样的权限情况下:Error Code: 1370. execute command denied to user 'query_all'@'%' for routine 'zjzc.loadTreeByParent'会权限不足,而且也看不到函数内容;加上执行权限后:GRANT SELECT , EXECUTE ON `zjzc`.* TO 'query_all'@'%';此时 可以执行函数,可以看到函数名,但是看不到函数内容
再分享一下我老师大神的人工智能教程吧。零基础!通俗易懂!风趣幽默!还带黄段子!希望你也加入到我们人工智能的队伍中来!https://blog.youkuaiyun.com/jiangjunshow