ACM青铜组第二题

本文介绍了一个使用C++实现的简单求和程序,该程序能够连续读取输入的整数对,并输出每一对整数的和,直到接收到特定的结束信号。通过此程序,初学者可以了解C++的基本输入输出操作以及简单的循环控制结构。

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题目描述:

Problem Description
Your task is to Calculate a + b.
Too easy?! Of course! I specially designed the problem for acm beginners.
You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.
Input
The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.
Sample Input
1 5
10 20
Sample Output
6
30

题意分析:
就是可以进行多次a+b的计算,直到ctrl+z。

#include<cstdio>
using namespace std;
int main()
{
	int a, b,sum;
	while (scanf("%d%d", &a, &b)!=EOF)
	{
		sum = a + b;
		printf("%d\n", sum);
	}
	return 0;
}

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