CodeForces - 1100B:Build a Contest(统计数字出现次数,满足条件输出)

博客讲述了如何协调一个包含不同难度问题的比赛。每场比赛需要n个不同难度的问题, Arkady每次创建一个问题并评估其难度,然后将其放入问题池。当池中有n个不同难度的问题时,他就会举行比赛。给定创建问题的顺序,需要确定每个问题是否导致了比赛的举行。

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B. Build a Contest
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Arkady coordinates rounds on some not really famous competitive programming platform. Each round features n problems of distinct difficulty, the difficulties are numbered from 1 to n.

To hold a round Arkady needs n new (not used previously) problems, one for each difficulty. As for now, Arkady creates all the problems himself, but unfortunately, he can’t just create a problem of a desired difficulty. Instead, when he creates a problem, he evaluates its difficulty from 1 to n and puts it into the problems pool.

At each moment when Arkady can choose a set of n new problems of distinct difficulties from the pool, he holds a round with these problems and removes them from the pool. Arkady always creates one problem at a time, so if he can hold a round after creating a problem, he immediately does it.

You are given a sequence of problems’ difficulties in the order Arkady created them. For each problem, determine whether Arkady held the round right after creating this problem, or not. Initially the problems pool is empty.

Input
The first line contains two integers n and m (1≤n,m≤105) — the number of difficulty levels and the number of problems Arkady created.

The second line contains m integers a1,a2,…,am (1≤ai≤n) — the problems’ difficulties in the order Arkady created them.

Output
Print a line containing m digits. The i-th digit should be 1 if Arkady held the round after creation of the i-th problem, and 0 otherwise.

Examples
input
3 11
2 3 1 2 2 2 3 2 2 3 1
output
00100000001
input
4 8
4 1 3 3 2 3 3 3
output
00001000
Note
In the first example Arkady held the round after the first three problems, because they are of distinct difficulties, and then only after the last problem.
题意:给出一个整数n,下面会给出m个数字,要你当第i个数字刚好能够与之前数字满足1~n,那么就输出1,否则输出0
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