题目链接
方向数组有12个,基础的bfs
#include<iostream>
#include<algorithm>
#include<queue>
#include<cstring>
using namespace std;
const int INF=0x3f3f3f3f;
struct Node{
int x,y,level;
}now,Next,start;
int x1,y1,x2,y2;
bool vis[110][110];
int dx[]={1,1,-1,-1,2,2,-2,-2, 2,2,-2,-2};
int dy[]={2,-2,2,-2,1,-1,1,-1, 2,-2,2,-2};
int bfs(int x,int y){
memset(vis,0,sizeof(vis));
start.x=x,start.y=y,start.level=0;
queue<Node> q;
vis[x][y]=1;
q.push(start);
while(!q.empty()){
now=q.front();
q.pop();
if(now.x==1&&now.y==1) return now.level;
for(int i=0;i<12;i++){
int nx=now.x+dx[i];
int ny=now.y+dy[i];
if(nx>=1&&nx<=100&&ny>=1&&ny<=100&&!vis[nx][ny]){
Next.x=nx,Next.y=ny,Next.level=now.level+1;
vis[nx][ny]=1;
q.push(Next);
}
}
}
return -1;
}
int main(){
cin>>x1>>y1>>x2>>y2;
int ans1,ans2;
ans1=bfs(x1,y1);
ans2=bfs(x2,y2);
cout<<ans1<<endl<<ans2<<endl;
}