PAT1028人口普查

最新推荐文章于 2022-08-11 10:50:13 发布

原创最新推荐文章于 2022-08-11 10:50:13 发布 · 188 阅读

1 ·

CC 4.0 BY-SA版权

文章标签：

#PAT #c++ #1028

拼题同时被 2 个专栏收录

2 篇文章

订阅专栏

PAT乙级

2 篇文章

订阅专栏

##PAT 人口普查1028
在这里插入图片描述

//人口普查
#include<iostream>
#include<vector>
#include<string>
#include<algorithm>
using namespace std;

struct person
{
	string name;
	int date;
};
int comp(person a, person b)
{
	return a.date < b.date;
}
int main()
{
	vector<person> people;
	person b;
	string name;
	int year, mouth, day;
	int minday = 18140905;
	int maxday = 20140907;
	int aday;
	int n;
	cin >> n;
	for (int i = 0;i < n;i++)
	{
		cin >> name;
		scanf("%d/%d/%d", &year, &mouth, &day);
		aday = year * 10000 + mouth * 100 + day;
		if (aday > minday&&aday < maxday)
		{
			b.name = name;
			b.date = aday;
			people.push_back(b);
		}
	}
	sort(people.begin(), people.end(), comp);
	if (people.size() == 0)
	{
		cout << "0" << endl;
	}
	else
	{
		cout << people.size() << " " << people[0].name << " " << people[people.size() - 1].name;
	}
	return 0;

}