1083 List Grades (25 分)(排序,水题)

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N

name[1] ID[1] grade[1]

name[2] ID[2] grade[2]

... ...

name[N] ID[N] grade[N]

grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

Sample Input 1:

4

Tom CS000001 59

Joe Math990112 89

Mike CS991301 100

Mary EE990830 95

60 100

Sample Output 1:

Mike CS991301

Mary EE990830

Joe Math990112

Sample Input 2:

2

Jean AA980920 60

Ann CS01 80

90 95

Sample Output 2:

NONE

#include <iostream>
#include <algorithm>
#include <cmath>
#include <vector>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <string>
#include <cctype>
#include <string.h>
#include <cstdio>
using namespace std;
struct node{
    string name,id;
    int grade;
};
bool cmp(node a,node b){
    return a.grade>b.grade;
}
int main(){
    int n,low,high;
    cin>>n;
    vector<node> stu(n);
    for(int i=0;i<n;i++)
        cin>>stu[i].name>>stu[i].id>>stu[i].grade;
    sort(stu.begin(),stu.end(),cmp);
    cin>>low>>high;
    int cnt=0;
    for(int i=0;i<n;i++){
        if(stu[i].grade>=low&&stu[i].grade<=high){
            cout<<stu[i].name<<" "<<stu[i].id<<endl;
            cnt++;
        }
    }
    if(cnt==0) cout<<"NONE";
    return 0;
}

 

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