PAT甲级1027 Colors in Mars

最新推荐文章于 2022-07-02 16:10:22 发布

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#PAT #甲级 #1027 #Colors in Mars

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本文介绍了一个将十进制颜色值转换为火星计算机中使用的十三进制RGB表示的问题。通过给出的示例代码，展示了如何使用字符数组进行转换，并强调了输出格式的重要性。

题目
1027 Colors in Mars (20 分)
People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input Specification:
Each input file contains one test case which occupies a line containing the three decimal color values.

Output Specification:
For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.

Sample Input:
15 43 71
Sample Output:
#123456

题意
就是输入三个十进制的数字，然后将其转换为十三进制的数，并按照一定的格式输出

注意：这道水题我刷了很久，需要重点注意的是，最后输出的时候一定要用%c输出，什么原因我也不太清楚，反正%d一直wa。

代码

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<cmath>

using namespace std;

int main()
{
    char hx[14]={"0123456789ABC"};
    int mz[4];
    scanf("%d%d%d",&mz[0],&mz[1],&mz[2]);

    printf("#");

    for(int i=0;i<3;i++)
    {
        int x = mz[i]%13;
        printf("%c%c",hx[mz[i]/13],hx[x]);
        //之前是printf("%d%c",mz[i]/13,hx[x]);,一直wa
    }
    return 0;
}