方法一
时间复杂度O(N)
参照leetcode官方答案
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode oddEvenList(ListNode head) {
if (head == null){
return null;
}
ListNode odd = head;
ListNode evenHead = head.next;
ListNode even = evenHead;
while (even != null && even.next != null){
odd.next = odd.next.next;
even.next = even.next.next;
odd = odd.next;
even = even.next;
}
odd.next = evenHead;
return head;
}
}
日期
2020-11-13