题目描述
请实现一个函数用来判断字符串是否表示数值(包括整数和小数)。例如,字符串"+100","5e2","-123","3.1416"和"-1E-16"都表示数值。 但是"12e","1a3.14","1.2.3","+-5"和"12e+4.3"都不是。
解题思路
表示数值的字符串遵循模式[A][.[B]][e|EC],A为数值的整数部分,B为数值的小数部分,C为指数部分,同时A和B不可以同时为空。A和C均为待符号的整数,而B为无符号整数。设两个函数,scanUndignedInteger判断是否为无符号整数,scanInteger为有符号整数,再分别对A,B,C三部分进行判断。
C++版
class Solution {
public:
bool isNumeric(char* str)
{
if(str == nullptr)
return false;
bool numeric = scanInteger(&str);
if(*str == '.'){
++ str;
numeric = scanUndignedInteger(&str) || numeric;
}
if(*str == 'e' || *str == 'E'){
++ str;
numeric = numeric && scanInteger(&str);
}
return numeric && *str == '\0';
}
bool scanInteger(char** str){
if(**str == '+' || **str == '-')
++(*str);
return scanUndignedInteger(str);
}
bool scanUndignedInteger(char** str){
char *before = *str;
while(**str != '\0' && **str >= '0' && **str <= '9')
++(*str);
return *str > before;
}
};
Python版
class Solution:
# s字符串
def __init__(self):
self.flag = True
def isNumeric(self, s):
# write code here
if len(s) == 0:
return False
if s[0] != '.':
cur = self.scanInteger(s, 0)
else:
cur = 0
if cur < len(s) and s[cur] == '.':
cur += 1
flag = self.flag
self.flag = True
cur = self.scanUnsignedInteger(s, cur)
self.flag |= flag
if cur < len(s) and (s[cur] == 'e' or s[cur] == 'E'):
cur += 1
cur = self.scanInteger(s, cur)
return self.flag and cur == len(s)
def scanInteger(self, s, cur):
if cur == len(s):
self.flag = False
elif s[cur] == '+' or s[cur] == '-':
cur += 1
tempcur = self.scanUnsignedInteger(s, cur)
return tempcur
def scanUnsignedInteger(self, s, cur):
temp = cur
while cur < len(s) and s[cur] >= '0' and s[cur] <= '9':
cur += 1
if cur == temp:
self.flag = False
return cur