C - Intense Heat

The heat during the last few days has been really intense. Scientists from all over the Berland study how the temperatures and weather change, and they claim that this summer is abnormally hot. But any scientific claim sounds a lot more reasonable if there are some numbers involved, so they have decided to actually calculate some value which would represent how high the temperatures are.

Mathematicians of Berland State University came up with a special heat intensity value. This value is calculated as follows:

Suppose we want to analyze the segment of n

consecutive days. We have measured the temperatures during these n days; the temperature during i-th day equals ai

.

We denote the average temperature of a segment of some consecutive days as the arithmetic mean of the temperature measures during this segment of days. So, if we want to analyze the average temperature from day x

to day y, we calculate it as i=xyaiyx+1 (note that division is performed without any rounding). The heat intensity value is the maximum of average temperatures over all segments of not less than k consecutive days. For example, if analyzing the measures [3,4,1,2] and k=3, we are interested in segments [3,4,1], [4,1,2] and [3,4,1,2]

(we want to find the maximum value of average temperature over these segments).

You have been hired by Berland State University to write a program that would compute the heat intensity value of a given period of days. Are you up to this task?

Input

The first line contains two integers n

and k (1kn5000

) — the number of days in the given period, and the minimum number of days in a segment we consider when calculating heat intensity value, respectively.

The second line contains n

integers a1, a2, ..., an (1ai5000) — the temperature measures during given n

days.

Output

Print one real number — the heat intensity value, i. e., the maximum of average temperatures over all segments of not less than k

consecutive days.

Your answer will be considered correct if the following condition holds: |resres0|<106

, where res is your answer, and res0

is the answer given by the jury's solution.

Example
Input
4 3
3 4 1 2
Output
2.666666666666667
AC代码(比赛的时候一直想着暴力没有想到用前缀和一直困在8上)

#include <iostream>

#include <bits/stdc++.h>
using namespace std;

int main()
{
       int n,k;
    cin>>n>>k;
    int m[5005];
    int sum[5005]={0};
    for(int i=0;i<n;i++){
        cin>>m[i];
        if(i!=0)
            sum[i]=sum[i-1]+m[i];
        else
            sum[i]=m[i];
    }
    int max=0;
    int p=1;
    for(int i=k;i<=n;i++){       //连续的数字个数
        for(int j=0;j<=n-i;j++){    //具体连续的数字是哪一些 n-i 就是i的最后一位
            int t;
            if(j==0)
                t=sum[j+i-1];
            else
                t=sum[j+i-1]-sum[j-1];
            if((double)t/i>(double)max/p){
                max=t;
                p=i;
            }
        }
    }
    printf("%.20lf\n",(double)max/p);
    return 0;
}

内容概要:本文介绍了奕斯伟科技集团基于RISC-V架构开发的EAM2011芯片及其应用研究。EAM2011是一款高性能实时控制芯片,支持160MHz主频和AI算法,符合汽车电子AEC-Q100 Grade 2和ASIL-B安全标准。文章详细描述了芯片的关键特性、配套软件开发套件(SDK)和集成开发环境(IDE),以及基于该芯片的ESWINEBP3901开发板的硬件资源和接口配置。文中提供了详细的代码示例,涵盖时钟配置、GPIO控制、ADC采样、CAN通信、PWM输出及RTOS任务创建等功能实现。此外,还介绍了硬件申领流程、技术资料获取渠道及开发建议,帮助开发者高效启动基于EAM2011芯片的开发工作。 适合人群:具备嵌入式系统开发经验的研发人员,特别是对RISC-V架构感兴趣的工程师和技术爱好者。 使用场景及目标:①了解EAM2011芯片的特性和应用场景,如智能汽车、智能家居和工业控制;②掌握基于EAM2011芯片的开发板和芯片的硬件资源和接口配置;③学习如何实现基本的外设驱动,如GPIO、ADC、CAN、PWM等;④通过RTOS任务创建示例,理解多任务处理和实时系统的实现。 其他说明:开发者可以根据实际需求扩展这些基础功能。建议优先掌握《EAM2011参考手册》中的关键外设寄存器配置方法,这对底层驱动开发至关重要。同时,注意硬件申领的时效性和替代方案,确保开发工作的顺利进行。
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值