Higher h-index
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 0 Accepted Submission(s): 0
Problem Description
The h
-index of an author is the largest h
where he has at least h
papers with citations not less than h
.
Bobo has no papers and he is going to publish some subsequently.
If he works on a paper for x
hours, the paper will get (a⋅x)
citations, where a
is a known constant.
It's clear that x
should be a positive integer.
There is also a trick -- one can cite his own papers published earlier.
Given Bobo has n
working hours, find the maximum h
-index of him.
Bobo has no papers and he is going to publish some subsequently.
If he works on a paper for x
It's clear that x
There is also a trick -- one can cite his own papers published earlier.
Given Bobo has n
Input
The input consists of several test cases and is terminated by end-of-file.
Each test case contains two integers n
and a
.
Each test case contains two integers n
Output
For each test case, print an integer which denotes the maximum h
-index.
## Constraint
* 1≤n≤10
9![]()
![]()
* 0≤a≤n![]()
* The number of test cases does not exceed 10
4![]()
.
## Constraint
* 1≤n≤10
* 0≤a≤n
* The number of test cases does not exceed 10
Sample Input
3 03 11000000000 1000000000
Sample Output
121000000000
Hint
For the first sample, Bobo can work $3$ papers for $1$ hour each.With the trick mentioned, he will get papers with citations $2, 1, 0$. Thus, his $h$-index is $1$.For the second sample, Bobo can work $2$ papers for $1$ and $2$ hours respectively. He will get papers with citations $1 + 1, 2 + 0$. Thus, his $h$-index is $2$.//h:有大于等于h篇的影响因子大于h的论文
#include <bits/stdc++.h>
using namespace std;
int a[200005];
int main()
{
int a,b;
while(~scanf("%d%d",&a,&b))
{
printf("%d\n",(a+b)/2);
}
return 0;
}