自测-5 Shuffling Machine (20分)

本文详细介绍了一种使用C语言实现的洗牌算法,通过数组和字符串操作完成对一副扑克牌的多次随机重排,展示了如何读取输入次数并根据此进行重复洗牌的过程。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

在这里插入图片描述
在这里插入图片描述

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char cards[55][4] = {"S1","S2","S3","S4","S5","S6","S7","S8","S9","S10","S11","S12","S13","H1","H2","H3","H4","H5","H6","H7","H8","H9","H10","H11","H12","H13","C1","C2","C3","C4","C5","C6","C7","C8","C9","C10","C11","C12","C13","D1","D2","D3","D4","D5","D6","D7","D8","D9","D10","D11","D12","D13","J1","J2"};
int index[55];
char res[55][4] = {"0"};
int main(){
    int repeatNumber,i,j;
    scanf("%d",&repeatNumber);
    for(i=0;i<54;i++){
        scanf("%d",&index[i]);;
    }
    for(i=0;i<repeatNumber;i++){
        for(j=0;j<54;j++){
            strcpy(res[index[j]-1],cards[j]);
        }
        for(j=0;j<54;j++){
            strcpy(cards[j],res[j]);
        }
    }
    int count=0;
    for(i=0;i<54;i++){
        if(count==0){
            printf("%s",res[i]);
            count++;
        }else{
            printf(" %s",res[i]);
        }
    }
}
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值