#include<stdio.h>
#include<math.h>
int main()
{
int i, j, n, number[100][100], count = 1;
scanf("%d", &n);
//螺旋矩阵n*n ,n/2就可以获得几个旋的个数;
for (i = 0; i <= n / 2; i++)
{
//打印向下数组; n=7时;
for (j =i ; j < n - i; j++) //down 0<7
number[j][n - i - 1] = count++; //06.16.26.36.46.56.66
//打印向前数组应当在输入的number上每次减去2位;
for (j = n - i - 2; j >= i; j--) //back; 5 >= 0
number[n - i - 1][j] = count++; // 65.64.63.62.61.60
//打印向上的数组(x,y)x变动;
for (j = n - i - 2; j >= i; j--) //up 5 >= 0
number[j][i] = count++; //50.40.30.20.10.00.
//打印向前数(x,y)y变动;
for (j = i+1; j <= n - i-2; j++) //forwad 1<5
number[i][j] = count++; // 01 02 03 04 05;
}
f
c语言:二维数组,螺旋矩阵打印。PTA;
最新推荐文章于 2024-01-03 17:23:49 发布