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List<Sort.Order> orders = new ArrayList<>(); orders.add(new Sort.Order(Sort.Direction.DESC, "sex")); orders.add(new Sort.Order(Sort.Direction.DESC, "name")); Sort sort = Sort.by(orders);

@Query(value = "SELECT COUNT(1) FROM tbl_task_recoder WHERE projectId IN(?1)", nativeQuery = true) Integer findAccomplishNumber(List<Integer> projectId); JPA @Query中使用IN时,需要注意参数一定要是List<&g...