CodeWars -Good vs Evil（未通过）

最新推荐文章于 2021-06-12 16:05:54 发布

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博主在CodeWars上遇到一个名为'Good vs Evil'的编程挑战，遭遇困难未能通过所有测试用例。问题在于字符串处理，涉及将数字字符串分割并求和，但无法查看完整的测试数据以定位错误。已提供的3个测试例子不足以找出问题所在。

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这是一个没有通过的并且找不到错误的一个题目，我自己找不到啊，先放上来，看看有没有大佬能够给我看看。。。

题目：

will have many battles with the forces of evil. Different races will
certainly be involved. Each race has a certain worth when battling
against others. On the side of good we have the following races, with
their associated worth:

Hobbits: 1 Men: 2 Elves: 3 Dwarves: 3 Eagles: 4 Wizards: 10 On the
side of evil we have:

Orcs: 1 Men: 2 Wargs: 2 Goblins: 2 Uruk Hai: 3 Trolls: 5 Wizards: 10
Although weather, location, supplies and valor play a part in any
battle, if you add up the worth of the side of good and compare it
with the worth of the side of evil, the side with the larger worth
will tend to win.

Thus, given the count of each of the races on the side of good,
followed by the count of each of the races on the side of evil,
determine which side wins.

Input: The function will be given two parameters. Each parameter will
be a string separated by a single space. Each string will contain the
count of each race on the side of good and evil.

The first parameter will contain the count of each race on the side of
good in the following order:

Hobbits, Men, Elves, Dwarves, Eagles, Wizards. The second parameter
will contain the count of each race on the side of evil in the
following order:

Orcs, Men, Wargs, Goblins, Uruk Hai, Trolls, Wizards. All values are
non-negative integers. The resulting sum of the worth for each side
will not exceed the limit of a 32-bit integer.

Output: Return "Battle Result: Good triumphs over Evil" if good wins,
"Battle Result: Evil eradicates all trace of Good" if evil wins, or
"Battle Result: No victor on this battle field" if it ends in a tie.

我的见解：就是给两字符串，然后里面的内容都是数字，并且是用空格相隔开的数据，先分隔成数组，然后根据获取数据相加，但是有错误啊，codewar有一点不好就是，我看不见测试数据啊！！

代码：

function goodVsEvil(good, evil){
    let goodRes = change(good);
    let evilRes = change(evil);
    let str;
    if(goodRes===evilRes){
       str= "Battle Result: No victor on this battle field";
    }else{
        goodRes >evilRes? str= 'Battle Result: Good triumphs over Evil':str="Battle Result: Evil eradicates all trace of Good";
    }
    return str;
 }
 
 function change(name){
     var str1 = name.split(' ');   
     var num =0;
     for(var i=0;i<str1.length;i++){
         num+=parseInt(str1[i]);
     }
     return num;
 }

显示通过93个没有通过28个，好密码。。

给予的三个测试例子：

Test.expect( goodVsEvil('1 1 1 1 1 1', '1 1 1 1 1 1 1') === 'Battle Result: Evil eradicates all trace of Good', 'Evil should win' );
Test.expect( goodVsEvil('0 0 0 0 0 10', '0 1 1 1 1 0 0') === 'Battle Result: Good triumphs over Evil', 'Good should win' );
Test.expect( goodVsEvil('1 0 0 0 0 0', '1 0 0 0 0 0 0') === 'Battle Result: No victor on this battle field', 'Should be a tie' );
`
唉~！``