Who's in the Middle

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本文介绍了一道编程题，任务是找出一群奶牛中产量处于中位数的奶量值。通过输入奇数个奶牛的产奶量，利用排序算法找到中位数并输出。示例给出了五个奶牛的数据及相应的中位数。

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题目链接
Problem Description
FJ is surveying his herd to find the most average cow. He wants to know how much milk this ‘median’ cow gives: half of the cows give as much or more than the median; half give as much or less.
Given an odd number of cows N (1 <= N < 10,000) and their milk output (1…1,000,000), find the median amount of milk given such that at least half the cows give the same amount of milk or more and at least half give the same or less.
Input

Line 1: A single integer N
Lines 2…N+1: Each line contains a single integer that is the milk output of one cow.
Output
Line 1: A single integer that is the median milk output.
Sample Input
5
2
4
1
3
5
Sample Output
3
Hint
INPUT DETAILS:
Five cows with milk outputs of 1…5
OUTPUT DETAILS:
1 and 2 are below 3; 4 and 5 are above 3.

解题报告:
注意点：
1.虽然题目要求输入一组，但是在编写程序的时候必须输入多组不然会出错
2.排序找最中间的数字

#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
using namespace std;
int main(){
    int n;
    while(cin>>n){
        int xx[10005];
        memset(xx,0,sizeof(xx));
        for(int i = 0;i<n;i++)
        scanf("%d",&xx[i]);
        sort(xx,xx+n);
        cout<<xx[n/2]<<endl;
    }
    return 0;
}