LeetCode-231-Power of Two-E（判断一个数是否是2的次幂）

Given an integer, write a function to determine if it is a power of two.

Example 1:

Input: 1
Output: true
Explanation: 2的0次幂 = 1

Example 2:

Input: 16
Output: true
Explanation: 2的4次幂 = 16

Example 3:

Input: 218
Output: false

代码：

 bool isPowerOfTwo(int n) {
        if(n==0)
            return false;
        while(n%2==0)
            n/=2;
        if(n==1)
            return true;
        else
            return false;
    }