题目描述:(题目来源:LeetCode)
如果我们可以将小写字母插入模式串 pattern 得到待查询项 query,那么待查询项与给定模式串匹配。(我们可以在任何位置插入每个字符,也可以插入 0 个字符。)
给定待查询列表 queries,和模式串 pattern,返回由布尔值组成的答案列表 answer。只有在待查项 queries[i] 与模式串 pattern 匹配时, answer[i] 才为 true,否则为 false。
示例 1:
输入:queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB"
输出:[true,false,true,true,false]
示例:
"FooBar" 可以这样生成:"F" + "oo" + "B" + "ar"。
"FootBall" 可以这样生成:"F" + "oot" + "B" + "all".
"FrameBuffer" 可以这样生成:"F" + "rame" + "B" + "uffer".
示例 2:
输入:queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa"
输出:[true,false,true,false,false]
解释:
"FooBar" 可以这样生成:"Fo" + "o" + "Ba" + "r".
"FootBall" 可以这样生成:"Fo" + "ot" + "Ba" + "ll".
示例 3:
输出:queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT"
输入:[false,true,false,false,false]
解释:
"FooBarTest" 可以这样生成:"Fo" + "o" + "Ba" + "r" + "T" + "est".
语言:Kotlin
解题思路:看到这个题目时,觉得这个题目的思路其实挺简单的,只需要将一个大字符串分解成多个小字符串,然后再判断每个小字符串中是否含有大写字母。但是在真正写的过程中,还是有些小细节需要注意,具体看代码吧,这个题目只需要细心就好了
class Solution {
fun camelMatch(queries: Array<String>, pattern: String): List<Boolean> {
val list = mutableListOf<Boolean>()
for (que in queries){
list.add(computer(que,pattern))
}
return list
}
private fun computer(query:String,pattern: String) : Boolean{
val list = mutableListOf<Int>()
for (pa in pattern){
if (list.size == 0){
if (pomputer2(query,pa.toString()) != -1) {
list.add(pomputer2(query, pa.toString()))
}else{
return false
}
}else if (list[list.lastIndex] != query.lastIndex){
if (pomputer2(query.substring(list[list.lastIndex]+1),pa.toString()) != -1) {
list.add(
pomputer2(
query.substring(list[list.lastIndex] + 1),
pa.toString()
) + list[list.lastIndex] + 1
)
}else{
return false
}
}
}
for (i in 0..list.lastIndex){
if (list[i] != 0){
if (i == 0){
for (j in query.substring(0,list[0])){
if (j in 'A'..'Z'){
return false
}
}
}else{
if (list[i-1]+1 != list[i]) {
for (j in query.substring(list[i - 1] + 1, list[i])){
if (j in 'A'..'Z'){
return false
}
}
}
}
if (i == list.lastIndex&&list[i]!=query.lastIndex){
for (j in query.substring(list[i]+1)){
if (j in 'A'..'Z'){
return false
}
}
}
}
}
return true
}
private fun pomputer2(query: String,pattern: String) :Int{
return query.indexOf(pattern)
}
}
fun main(){
println("${Solution().camelMatch(arrayOf("FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"),"FoBaT")}")
}//输出为[false, true, false, false, false]