字符串相互拆解又相互合并并去重。

最新推荐文章于 2025-06-11 00:15:00 发布

Komeribiii

最新推荐文章于 2025-06-11 00:15:00 发布

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分类专栏： java

本文链接：https://blog.youkuaiyun.com/qq_37568049/article/details/88227025

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本文介绍了一种处理和合并字符串的Java方法，该方法通过正则表达式和StringBuilder类实现字符串的拆分、去重和合并。具体步骤包括：1) 使用split方法按逗号拆分字符串；2) 使用正则表达式提取数字和字母部分；3) 去除重复字母；4) 将处理后的字符串重新合并。

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1.业务是给T65ABCA,78DEFD,利用split(",")拆分成T65ABCA和78DEFD，单独分别并合并。第一个分解合并并且去重变成T65A,T65B,T65C，第二个分解合并并且去重变成78D,78E,78F.

2.代码

public class ModelTest {

    @Test
    public void test() {
        String str = "T42KBCK,32ABCA";
        String str1 = "56BFGB";
        String[] arr = str.split(",");
        String seatNum;
        String letter;
        StringBuilder lastStr = new StringBuilder();
        if (arr.length > 0) {
            for (int i = 0; i < arr.length; i++) {
                String regEx = "\\D";\
                Pattern p = Pattern.compile(regEx );
                Matcher m = p.matcher(arr[i]);
                String result = m.replaceAll("").trim();
                int length = result.length();
                Character ch = result.charAt(0);
                int index = arr[i].indexOf(ch);
                seatNum = arr[i].subString(0,index+length);
                letter = arr[i].subString(index+length,arr[i].length());
                lastStr.append(merge(seatNum, letter));
            }
        }
        //去掉最后的逗号
        String result  = lastStr.substring(0,lastStr.length()-1);
        System.out.println("最后的结果:"+result);
    }
    
    
    

    
    /**
      * merge(合并的方法)
      * @param seatNum
      * @param ss
      */
    private String merge(String seatNum, String letter) {
        //去掉重复的字母
        String handleStr = letter.replaceAll("(.)(?=.*\\1)", "");
        StringBuilder builder = new StringBuilder();
        for (int i = 0; i < handleStr.length(); i++) {
            String subStr = handleStr.substring(i, i + 1);
            builder.append(seatNum).append(subStr).append(",");
        }
        return builder.toString();
    }

}

第二种
@Test
    public void testModeContext() {
        String str = "T42KBCK,32ABCA";
        String str1 = "56BFGB";
        String[] arrVal = str1.split(",");
        String seatNum;
        String letter;
        StringBuilder lastStr = new StringBuilder();
        if (arrVal.length > 0) {
            for (int i = 0; i < arrVal.length; i++) {
                //判断首字符是字母还是数字
                String firstStr = arrVal[i].substring(0, 1);
                String arr = arrVal[i].trim();
                Matcher matcher = Pattern.compile("[0-9]").matcher(arr);
                if (matcher.find()){
                        seatNum = arr.substring(0, matcher.end()+1);
                        letter = arr.substring(matcher.end()+1, arr.length());
                        lastStr.append(merge(seatNum,letter));
                }
            }
        }
        //去掉最后的逗号
        String result  = lastStr.substring(0,lastStr.length()-1);
        System.out.println("最后的结果:"+result);
    }
    
    
    

    
    /**
      * merge(这里用一句话描述这个方法的作用)
      * @param seatNum
      * @param ss
      */
    private String merge(String seatNum, String letter) {
        //去掉重复的字母
        String handleStr = letter.replaceAll("(.)(?=.*\\1)", "");
        StringBuilder builder = new StringBuilder();
        for (int i = 0; i < handleStr.length(); i++) {
            String subStr = handleStr.substring(i, i + 1);
            builder.append(seatNum).append(subStr).append(",");
        }
        return builder.toString();
    }