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ajax传参数json对象到后台获取
var data = {data:{name:'pxxx', paramData:[{dataSource:'a1',table:'t1',field:'f1','r':[{name1:"01",p:''},{name2:"02",p:'10,100'},{name2:"01",p:''}]}, {da...原创 2018-07-04 11:37:10 · 50187 阅读 · 2 评论 -
几种ajax传参数到后台获取的方法
传参: $.ajax({ type:"post", dataType:"json", url:"DataSourceCheck/refreshDataSource", data:{dataSourceId:dsId}, success: function(data){ //你的逻...原创 2019-04-12 15:13:24 · 13674 阅读 · 0 评论